Question

(sin^2x)/(1-cos^2x)​

Answer 1

Step-by-step explanation:

sin²x/1-cos²x

1-cos²x/1-cos²x

[sin²A + cos²A = 1](sin²A = 1- cos²A)

1 ans

Answer 2

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$\large\mathcal\red{solution}$

$\frac{ \sin {}^{2} (2a) }{1 - \cos {}^{2} (a) } \\ = \frac{4 \sin {}^{2} (a) \cos {}^{2} (a) }{ \sin {}^{2} (a) } \\ = 4 \cos {}^{2} (a)$

$\large\mathcal\red{hope\: this \: helps \:you......}$