Physics, asked by giridharb1983, 1 year ago

sin 2x by anintio
method

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Answered by Anonymous

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· I=∫sin2x dx. =∫sinx⋅sinx d x. =∫sinx⋅ddx(−cosx) dx. which by IBP becomes... I=−sinxcosx+∫ddx(sinx)⋅cosx dx

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