Question

sin^2x+cos^2x find dy/ dx​

Answer 1

Answer:

Answer

We have sin

2

x+cos

2

y=1

Differentiating both sides w.r.t. x, we obtain

dx

d

(sin

2

x+cos

2

y)=

dx

d

(1)

⇒2sinx.

dx

d

(sinx)+2cosy.

dx

d

(cosy)=0

⇒2sinxcosx+2cosy(−siny).

dx

dy

=0

⇒sin2x−sin2y

dx

dy

=0

∴

dx

dy

=

sin2y

sin2x