sin^2x . cos^2y _cos^2x.sin^2y
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Step-by-step explanation:
please wrute ut properly what to find inits
Answered by
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Answer:
sin^2x-sin^2y =sin (A+B).sin (A-B)
Step-by-step explanation:
sin^2x.cos^2y-cos^2x.sin^2y
sin^2x. (1-sin^2y)-cos^2x.sin^2y
= sin^2x-sin^2y.sin^2x-cos^2x.sin^2y
= sin^2x-sin^2y (sin^2x+cos^2x)
=sin^2x-sin^2y
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