Math, asked by adityakcvn11a, 7 months ago

sin^2x . cos^2y _cos^2x.sin^2y​

Answers

Answered by anubhavgupta357
0

Step-by-step explanation:

please wrute ut properly what to find inits

Answered by aryanjangra53
0

Answer:

sin^2x-sin^2y =sin (A+B).sin (A-B)

Step-by-step explanation:

sin^2x.cos^2y-cos^2x.sin^2y

sin^2x. (1-sin^2y)-cos^2x.sin^2y

= sin^2x-sin^2y.sin^2x-cos^2x.sin^2y

= sin^2x-sin^2y (sin^2x+cos^2x)

=sin^2x-sin^2y

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