sin 2x=sin 60 cos 30 -cos 60 sin30
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ANSWER:---------
We know that Here, we have {cos(2x) = cos(60°)cos(30°) + {sin(60°)sin(30°)Hence, sin(2x) = {sin(90°) We know that sin(90°) = {1Hence, sin(2x) = 1}
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Answered by
22
2 ways to do this
Method 1:
Put the value since we know these standard values
sin2x=[(√3/2)*(√3/2)]-[(1/2)*(1/2)]
=3/4-1/4
=2/4
=1/2
=sin 30
2x=30
x=15°
Method 2:Using sin(a-b)
If you observe the RHS carefully it is actually sin (a-b)
since sin(a-b)=sina*cosb-cosa*sinb
hence sin2x=sin(60-30)
sin2x=sin30
2x=30
x=15°
Hope it helps
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