Question

sinα =√3/2 ,cosβ=0,then find β-α​

Answer 1

Answer:

sin$\alpha$ = ${\sqrt{3}}$/2

sin60⁰ =${\sqrt{3}}$/2

comparing these angles,

$\alpha$ = 60⁰

cos$\beta$ = 0⁰

cos90⁰ = 0

comparing these angles

$\beta$ = 90⁰

HOPE IT HELPS...

Answer 2

$\huge\star{\underline{\underline{\tt{\red{Answer:}}}}}\star$

$\large\star{\green{\mathfrak{\underline{Explanation:}}}}$

__________________________

$\sin( \alpha ) = \frac{ \sqrt{3} }{2} \: \\ \\ \cos( \beta ) = 0$

We know That

Sin$\frac{\sqrt{3}}{2}$ =60°

Therefore,

$\alpha$=60°

Also,We know that

Cos(0)=90°

Therefore,

$\beta$=90°

From This

$\beta$-$\alpha$=90°-60°

=30°

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