Sinα=3/5 and cosβ=9/41
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sinA=3/5
cosA= √1-sin²A = √1-(3/5)²= √1-9/25=√16/25
cosA= 4/5
cos B = 9/41
like this Sin B= 40/41 than what tell me what is your problems
cosA= √1-sin²A = √1-(3/5)²= √1-9/25=√16/25
cosA= 4/5
cos B = 9/41
like this Sin B= 40/41 than what tell me what is your problems
ksiddharth719:
Worng
Ok
Sinα=3/5 and cos=9/41 find the value of sin(α+β) and cos(α-β)?
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