sin∅ =3/5, cos∅ =4/5 Find other trigonometric ratios.
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2
Hey there!
>>sin∅ =3/5
>> cos∅ =4/5
We know that
>>tan∅ = sin∅/cos∅
>> cot∅ = cos∅/sin∅
>> sec∅= 1/cos∅
>> cosec∅ = 1/sin∅.
tan∅= (3/5)/(4/5) =3/4
cot∅= (4/5)/(3/5) =4/3
sec∅= 1/(4/5) =5/4
cosec∅= 1/(3/5) =5/3.
Hope helped!
>>sin∅ =3/5
>> cos∅ =4/5
We know that
>>tan∅ = sin∅/cos∅
>> cot∅ = cos∅/sin∅
>> sec∅= 1/cos∅
>> cosec∅ = 1/sin∅.
tan∅= (3/5)/(4/5) =3/4
cot∅= (4/5)/(3/5) =4/3
sec∅= 1/(4/5) =5/4
cosec∅= 1/(3/5) =5/3.
Hope helped!
Answered by
0
sintheta=3/5 at angle 37 °
and cos theta =4/5 at angle 37 °
then tan theta= sin/cos= 3/4
cotangent theta = 4/3
secant theta= 1/cos=5/4
cosecant theta= 1/sin = 5/3
and cos theta =4/5 at angle 37 °
then tan theta= sin/cos= 3/4
cotangent theta = 4/3
secant theta= 1/cos=5/4
cosecant theta= 1/sin = 5/3
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