Question

sinβ=3/5. find tanβ​

Answer 1

Answer:

hope this helps u

pls mark it as the brainliest

Answer 2

Step-by-step explanation:

$\sin( \beta ) = \frac{3}{5}$

$\cos( \beta ) = \sqrt{1 - \sin {}^{2} ( \alpha ) }$

$\sqrt{1 - ( \frac{3}{5}) {}^{2} }$

$\sqrt{ \frac{16}{25} }$

$\frac{4}{5}$

$\tan( \beta ) = \frac{ \sin( \beta ) }{ \cos( \beta ) }$

$\frac{ \frac{3}{5} }{ \frac{4}{5} }$

$\frac{3}{4}$

<(￣︶￣)↗