Math, asked by lloydzanepk, 10 months ago

Sin∝=-3/5 where π∠∝∠3π/2 then the value of cos∝/2 is....plz give the right answer

Answers

Answered by jaiprakashtiwari816
0

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Answered by arpitzarkart56
1

Answer:

In this way:

(Without further information about the angle #A#, I assume that that angle is in the first quadrant)

#sinA=sqrt(1-cos^2A)=sqrt(1-25/169)=sqrt((169-25)/169)=#

#=sqrt(144/169)=12/13#,

and

#tanA=sinA/cosA=(12/13)/(5/13)=12/13*13/5=12/5#

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