sin(3π-A)cos(A-π/2)tan(3π/2)÷cosec(13π/2+A)sec(3π+A)cot(A-π\2)
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Given : sin(3π-A)cos(A-π/2)tan(3π/2-A)÷cosec(13π/2+A)sec(3π+A)cot(A-π\2)
To Find : Simplify
Solution:
sin(3π-A) = Sin(2π+π-A) = Sin(π-A) = SinA
cos(A-π/2) = Cos(π/2 - A) = SinA
tan(3π/2-A) = CotA
cosec(13π/2+A) = cosec(π/2+A) = secA
sec(3π+A ) = sec(π+A ) = -secA
cot(A-π\2) = -tanA
SinA . SinA . CotA / ( ( secA )(-secA )(-tanA)
= SinA cosA / sec²AtanA
= CosAcosA. cos²A
= Cos⁴A
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