sin 3θ= cos(θ-26) Solve for θ
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Answered by
6
[tex]Sin 3 \alpha = cos ( \alpha - 26) \\
sin 3 \alpha = Sin (90 + \alpha - 26) \\
3 \alpha = 64 + \alpha \ \ or \ \ 3 \alpha = 180 - (64 + \alpha ) \\
So, 2 \alpha = 64\ \ or 4 \alpha = 116 \\
\alpha = 32\ deg\ \ OR\ \ alpha = 29\ deg \\
[/tex]
Here we use sin 90+α = cos α
Here we use sin 90+α = cos α
Answered by
126
Given :
- sin3θ = cos(θ - 26°)
To Find :
- Value of θ
Solution :
⟹ sin3θ = cos(θ - 26°)
⟹ sin3θ = sin [90° - (θ - 26°) ]
⟹ sin3θ = sin [90° - θ + 26°]
⟹ 3θ = 90° - θ + 26°
⟹ 3θ + θ = 90° + 26°
⟹ 4θ = 90° + 26°
⟹ 4θ = 116°
⟹ θ = 116° / 4
⟹ θ = 29°
Thus Value of θ = 29°
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