Question

sin^3+cos^3/1-2 cos^2=sec-sin/tan-1

Answer 1

Step-by-step explanation:

(sin3x+cos3x)/(1-2cos2x)

=(sinx+cosx)(sin2x - sinx cosx +cos2x)/(sin2x-cos2x)=

=(sinx+cosx)(1 - sinx cosx)/[(sinx-cosx)(sinx +cosx)]=

=(1 - sinx cosx)/(sinx-cosx)=||=

=(1/cosx-sin x)/(tanx-1)=(sec x- sinx)/(tanx -1)

i hope it will help you.