sin^3+cos^3/sin+cos +sincos
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this is wrong may be...
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Answer:
1
Step-by-step explanation:
identity used is (a^3+b^3)=(a+b)(a^2+b^2-ab)
=sin^3+cos^3/(sin+cos)+sincos
=(sin^2+cos^2-sincos)+sincos
=1-sincos+sincos
=1
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