sin^3 (logx 10) differentiate
Answers
Answered by
0
Answer:
ANSWER
using chain rule h(x)=g(f(x))
h
′
(x)=g
′
(f(x))⋅f
′
(x)
also the formula
dx
d
=log
a
x=
1na
1
⋅
x
1
we can differentiate y=log
10
sinx with respect to x as
dx
dy
=
dx
d
(log
10
sinx)
=
1na
1
⋅
x
1
⋅
dx
d
sinx
=
1na
1
⋅
x
1
⋅(cosx)
x
cosx
⋅
1na
1
Similar questions