Question

Sin [π/3 - sin^-1 (-1/2) ]​

Answer 1

Answer:

$\sin( \frac{\pi}{3 } - { \sin}^{ - 1}( \frac{ - 1}{2} ) ) \\ \\ .properties \: of \: { \sin }^{ - 1} ( - x) = - { \sin}^{ - 1} \\ \ { \sin }^{ - 1}( \frac{ - 1}{2}) = \frac{\pi}{6} \\ \\ \sin( \frac{\pi}{3} + \frac{\pi}{6} ) \\ \sin( \frac{2\pi + \pi}{6} ) \\ \sin( \frac{3\pi}{6} ) \\ \sin( \frac{\pi}{2} ) \\ = 1$

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