Question

(sin^3 theta + cos^3 theta) ÷ (sin theta + cos theta)

Answer 1

sin^3θ+cos^3θ=(sinθ+cosθ)sin^2+cos^2θ-sinθcosθ)

(sin^3 θ + cos^3 θ) ÷(sin θ+ cos θ) =(sinθ+cosθ)sin^2+cos^2θ-sinθcosθ)÷(sin θ+ cos θ)

=1-sinθcosθ