Question

sin^3(π+x) sec^2(π-x)tan(2π-x)/cos^2(π/2+x)sin(π-x)cosec^2-x=tan^3
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Answer 1

Step-by-step explanation:

sin(sin−1x) = x, if -1 ≤ x ≤ 1

cos(cos−1x) = x, if -1 ≤ x ≤ 1

tan(tan−1x) = x, if -∞ ≤ x ≤∞

cot(cot−1x) = x, if -∞≤ x ≤∞

sec(sec−1x) = x, if -∞ ≤ x ≤ -1 or 1 ≤ x ≤ ∞

cosec(cosec−1x) = x, if -∞ ≤ x ≤ -1 or 1 ≤ x ≤ ∞

Also, the following formulas are defined for inverse trigonometric functions.

sin−1(sin y) = y, if -π/2 ≤ y ≤ π/2

cos−1(cos y) =y, if 0 ≤ y ≤ π

tan−1(tan y) = y, if -π/2 <y< π/2

cot−1(cot y) = y if 0<y< π

sec−1(sec y) = y, if 0 ≤ y ≤ π, y ≠ π/2

cosec−1(cosec y) = y if -π/2 ≤ y ≤ π/2, y ≠ 0

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