Math, asked by sudharshangopinath, 10 months ago

sin 30 \cos 45+ cot 45\sec60-sin 60\tan45+cos30\sin90

Answers

Answered by 123Pratham
6

Answer: [ 1 + √2 - 2√3 ] / 2

Step-by-step explanation:

Hey there!

We know that,

sin30 = 1/2

cos45 = 1/√2

cot45 =1

sec60 = 2

sin60 = √3/2

tan45 = 1

cos30 = √3/2

sin90 = 1 .

sin30°/cos45° + cot45°/sec60° - sin60°/tan45° - cos30°/sin90°

= 1/2 ( 1/√2 ) + 1 / ( 2 ) - (√3/2 ) / ( 1 ) - (√3/2 ) / 1

= (√2 / 2 )+ 1/2+ ( - √3/2 ) - ( √3/2 )

= [√2/2 + 1/2 - 2√3] /2

= [√2 + 1 - 2√3 ]/2

=[ 1 + √2 - 2√3 ] / 2

Hope helped!

Similar questions