Question

sin 30 = cos (θ – 6°) where 30 and (θ – 6°) are both acute angles, find the value of θ.​

Answer 1

Answer:

Correct option is

A

24

Sin3θ=Cos(θ−6

∘

)

Cos(90−3θ)=Cos(θ−6

∘

)

90

0

−3θ=θ−6

96=4θ

θ=24

∘

Answer 2

$\huge⚘ \bf \ \red{Answer}$

30, θ-6 are acute angle

We know that sin (90 - θ) = cos θ

Sin 3θ = sin (90 – (θ - 6°))

Sin 3θ= sin(90 - θ + 6°)

Sin 3θ = sin (96° - θ)

3θ = 96° - θ

4θ = 96°

$θ = \dfrac{96 ^{0} }{ {4}^{0} }$

θ = 4⁰

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