sin 30 = cos (θ – 6°) where 30 and (θ – 6°) are both acute angles, find the value of θ.
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Sin 3θ = cos (θ – 6°) where 3 θ and θ − 6° are acute angles, find the value of θ. trigonometry class-10Read more on Sarthaks.com - https://www.sarthaks.com/34415/if-sin-3-cos-6-where-3-and-6-are-acute-angles-find-the-value-of
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If `sin30=cos(theta-6^0),` -
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