Question

sin 30 = cos (θ – 6°) where 30 and (θ – 6°) are both acute angles, find the value of θ.​

Answer 1

Explanation:

   sin25∘cos65∘+cos25∘sin65∘

=sin25∘sin(90∘−65∘)+cos25∘cos(90∘−65∘)

=sin25∘sin25∘+cos25∘cos25∘

=sin225∘+cos225∘

=1

Answer 2

Sin3θ=Cos(θ−6∘ )

Cos(90−3θ)=Cos(θ−6 ∘ )

90 ⁰ −3θ=θ−6

96=4θ

θ=24 ∘