Question

sin 30 degree + tan 45 degree minus cosec 45 degree divided by sin 30 degree + Cos 60 degree minus cot 45 degree find the value

Answer 1

Proper Question :

Sin 30° + tan 45° - Cosec 45° / Sin 30° + Cos 60° - Cot 45°


✏ 1/2 + 1 - √2 / 1/2 + 1/2 - 1

✏ 1+2/2 - √2 / 1+1/2 - 1

✏ 3/2 - √2 / 2/2 - 1

✏ 3/2 - √2 ÷ 1 - 1

✏ 3/2 - √2 ÷ 0

✏ ∞

Answer 2

$<b>$
Solution:-

$= > \frac{ sin30 + tan45 - cosec45}{sin30 + cos60 - cot45} \\ \\ = > \frac{ \frac{1}{2} + 1 - \sqrt{2} }{ \frac{1}{2} + \frac{1}{2} - 1 } \\ \\ = > \frac{ \frac{1 + 2 - 2 \sqrt{2} }{2} }{ \frac{1 + 1 - 2}{2} } \\ \\ = > \frac{3 - 2 \sqrt{2} }{0} \\ \\ = > \infty$