Sin 30
sec 30x tan 30°
Answers
Answer:
1/2×2/root3×1/root 3
Answer: sin 30 = 1/2; sec30 * tan 30 = 2/3
Step-by-step explanation:
Consider an equilateral triangle ABC. SInce each angle in an equilateral triangle is 600, therefore ∠A=∠B=∠C=60∘
Draw the perpendicular line AD from A to the side BC
Now ΔABD≅ΔACD
Therefore BD=DC and also
∠BAD=∠CAD
Now observe that the triangle ABD is a right triangle, right angled at D with ∠BAD=30∘ and ∠ABD=60∘.
As you know , for finding the trigonometric ratios, we need to know the lengths of the sides of the triangle. So, let us suppose that AB=2a
BD=12BC=a
To find the sin 30 degree value , let’s use sin 30 degree formula and it is written as
Sin 30 = opposite side/hypotenuse side
We know that, Sin 30= BD/AB = a/2a = 1 / 2
Therefore Sin 30 degree equals to the fractional value of 1/ 2.
Sin 30 = 1 / 2
Similarly we can derive the cos 30, tan 30 values as
Cos 30 = adjacent side / hypotenuse
Tan 30 = opposite side / adjacent side
The cosec 30, sec 30, and cot 30 values are found by reciprocating the values of sin 30, cos 30, and tan 30 respectively
Sin30° = 1/2
Cos30° = √3 / 2
Tan30° = 1 / √3
Cosec30° = 2
Sec30° = 2 / √3
Cot30° = √3
Sec30° * tan30° = (2/√3) * (1/√3) = 2/3
Please brainlist my answer, if Helpful!