Question

sin 30 + tan 45 - Cos 60 upon sec 30 + Cos 60 + cot 45​

Answer 1

[sin (30°) + tan (45°) - cos (60°)]

--------------------------------------------------

[sec (30°) + cos (60°) + cot (45°)]

[(1/2) + (1) - (1/2)]

= ----------------------------------------------------

[ ( root (3 )/ 2 ) + (1/2) + (1)]

By solving it,

2

= ---------------------

( root (3) +3)

By rationalising the denominator,

2root (3 )- 6

= --------------------------

3 - 9

2 [ 3 - root (3)]

= -----------------------

6

3- root (3)

= --------------------

3

= 1 - root (3)/3

= 1- 0.57

= 0.43

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Answer 2

Answer is 0.43

It is quite simple just put values of above .

I want to tell you trick of this .May be you know that.

For sin we have to write .

0 1 2 3 4

Then we have to divide it by 4.

0 1/4 1/2 3/4 1

Then we take square root on it.

0 1/2 1/root (2) root(3)/ 2 1

0° 30° 45° 60° 90°[ For]

Then we can find any value .

*for cos, reverse series.

*for tan ,divide series of sin by series of cos

*for cot,sec and cosec , reciprocal the series of tan ,cos and sin respectively.