Question

sin 30+ tan 45º - Cosec 60 /
Cot 45 + cos 60- sec30
​

Answer 1

$\frac{ \sin30 + \tan45 - \cosec60}{ \cot45 + \cos60 - \sec30 }$

$\frac{sin(90 - 60) + tan(90 - 45) - cosec(90 - 30)}{cot45 + cos60 - sec30}$

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$sin(90 - a) = cos \: a \\ tan(90 - a) = cot \: a \\ cosec(90 - a) = sec \: a$

$\frac{cos60 + cot45 - sec30}{cos60 + cot45 - sec30}$

$1$

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