Question

sin 30⁰+ tan450- cosec60⁰/ cot 45⁰+ cos60⁰-sec30⁰​

Answer 1

Step-by-step explanation:

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Answer 2

$given \: \\ \frac{ \:sin30 + tan45 - cosec60}{sec30 + cos60 + cot45} \\ answer : \\ \frac{43 - 24 \sqrt{3} }{11} \\ solution : \\ = > \frac{ \frac{1}{2} + 1 \frac{ - 2}{ \sqrt{3} } }{ \frac{2}{ \sqrt{3} + \frac{1}{2} + 1 } } \\ = > \frac{ \frac{ \sqrt{3} + 2 \sqrt{3} - 4 }{2 \sqrt{3} } }{ \frac{4 \sqrt{3 + 2 \sqrt{3} } }{2 \sqrt{3} } } \\ = > \frac{ \frac{ \sqrt{3} + 2 \sqrt{3} - 4 }{} }{4 + \sqrt{3} + 2 \sqrt{3} } \\ = > \frac{ 3 \sqrt{3} - 4 }{3 \sqrt{3} + 4 } \times \frac{3 \sqrt{3} - 4}{3 \sqrt{3} - 4} \\ = > \frac{(3 \sqrt{3} - 4) {}^{2} }{(3 \sqrt{3}) {}^{2} - (4) {}^{2} } \\ = > \frac{27 - 24 \sqrt{3} + 16}{27 - 16} \\ \\ = > \frac{43 - 24 \sqrt{3} }{11}$