Question

(Sin 30° +Cos 30°

)-( Sin 60° +Cos 60°)​

Answer 1

Answer:

0

Step-by-step explanation:

(Sin 30° +Cos 30°)-( Sin 60° +Cos 60°)

=(1/2+root3/2)-(root3/2+1/2)

=(1+root3/2)-(1+root3/2)

=0

Answer 2

Step-by-step explanation:

$sin30 = \frac{1}{2}$

$cos \: 30 = \frac{ \sqrt{3} }{2}$

$sin60 = \frac{ \sqrt{3} }{2}$

$cos60 = \frac{1}{2}$

(sin30+cos30) - (sin60+cos 60)=

$( \frac{1}{2} + \frac{ \sqrt{3} }{2}) - ( \frac{ \sqrt{3} }{2} + \frac{1}{2} ) = 0$