Math, asked by faisalpasha6364, 10 months ago

(sin 30°× cos 45°)+(cos 60°×45°)​

Answers

Answered by Anonymous
1

Answer:

Step-by-step explanation:

sin 30 = 1

cos 45 = root 3/2

cos 60 = 1/2

cos 45 = 1/root 2

(1*root 3/2 ) + ( 1/2 * 1/root 2 )

(root 3/2) + (1/2 root 2)

(3 root 6/4 root 2) + (2/4 root 2)

=2+3 root 6/4 root

2 + 3\sqrt{6} ÷ 4\sqrt{2}

Answered by Anubhab133
0

(sin 30°× cos 45°)+(cos 60°×45°)​

=(sin30°×cos45°)+ [cos(90°-60°)×cos45°]

=(sin30°×cos45°)+ (sin30°×cos45°)

= 1

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