Math, asked by shanmarlo007, 5 months ago

Sin 30° / cos 45° + tan 45° /sec 60°-sin60°/cos 45° - cos 30° /Sin 90°​

Answers

Answered by shibupdali
0

Answer:

Step-by-step explanation:

(cos0  

o

+sin45  

o

+sin30  

o

)(sin90  

o

−cos45  

o

+cos60  

o

)

=(1+  

2

​  

 

1

​  

+  

2

1

​  

)(1−  

2

​  

 

1

​  

+  

2

1

​  

)

=(1+  

2

1

​  

+  

2

​  

 

1

​  

)(1+  

2

1

​  

−  

2

​  

 

1

​  

)

=(  

2

3

​  

+  

2

​  

 

1

​  

)(  

2

3

​  

−  

2

​  

 

1

​  

)

=(  

2

3

​  

)  

2

−(  

2

​  

 

1

​  

)  

2

 

=  

4

9

​  

−  

2

1

​  

=  

4

7

​  

 

Answered by amitsnh
1

Step-by-step explanation:

sin 30° = 1/2

cos45° = 1/√2

tan45°=1

sec60° = 2

sin60° = √3/2

cos30° = √3/2

sim90° = 1

putting above values in the eqn we have

(1/2)/(1/√2) + 1/2 - (√3/2)/(1/√2) - (√3/2)/1

= (√2/2) + 1/2 - √6/2 - √3/2

= (√2 + 1 - √6 - √3)/2

= (√2 + 1 -√2*√3 - √3)/2

(√2 + 1 -√3(√2 + 1))/2

(√2 + 1)(1 - √3)/2

= - (√2 + 1)(√3 - 1)/2

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