Question

sin 30° cos 60° - sin^ 45 cos^2+ tan 60 =​

Answer 1

Answer:

Given:

2 \tan 45tan45 ° + \cos 60cos60 ° - \sin 30sin30 °

We have to find, the value of 2 \tan 45tan45 ° + \cos 60cos60 ° - \sin 30sin30 ° = ?

Solution:

∴ 2 \tan 45tan45 ° + \cos 60cos60 ° - \sin 30sin30 °

= 2(1) + \dfrac{1}{2}

2

1

- \dfrac{1}{2}

2

1

Using the trigonometric identity:

\tan 45tan45 ° = 1, \cos 60cos60 ° = \dfrac{1}{2}

2

1

and \sin 30sin30 ° = \dfrac{1}{2}

2

1

= 2 + \dfrac{1}{2}

2

1

- \dfrac{1}{2}

2

1

= 2

∴ 2 \tan 45tan45 ° + \cos 60cos60 ° - \sin 30sin30 ° = 2

Thus, the value of 2 \tan 45tan45 ° + \cos 60cos60 ° - \sin 30sin30 ° = 2.

Answer 2

1. answer- the answer is 2 and 10th bord question

step by step answer-

as we know 45°=1

cos 60°=1/2

sin 30°=1/2

put the value and you would get the

answer as 2°