Math, asked by 77mounishv, 9 months ago

sin 30° cot 450 sin 60° COS 30°
cos 450 sec 60° tan 450 sin 90°
tan? 60° + 4 cos? 45° +3 cos ec? 60° + 2 cos? 90°
2 cos ec30° +3 sec 60° - cot 30°
7. 4(sin^30° + cos* 60°) – 3(cos? 45° - sin’90°)+5 cos? 90
8. o po to 300 -2 cos? 45° – sin’oº
1 _1tan² 45° - 8 sinº 90°
sin 30° 2'
cos? 30°. with steps please​

Answers

Answered by propstaged
0

Answer:

Step-by-step explanation:

8. o po to 300 -2 cos? 45° – sin’oº

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