Question

sin 30° - Sin 90°+ 2 cos o
Tam 30 x tan 60
​

Answer 1

Your question

Find the value of

$\frac{(sin30\° - sin 90\° + 2 cos0\°)} {(tan30\° * tan60\°)}$

Solution :

sin 30° =  $\frac{1}{2}$

sin 90° = 1  

cos 0° = 1 ⇒ 2cos0° = 2

tan 30° = $\frac{1}{ \sqrt{3} }$

tan 60° = √3

Calculation :-

$\frac{\frac{1}{2}- 1 + 2 }{ \frac{1 * \sqrt{3} }{\sqrt{3} } }\\\\\\= \frac{1}{2} - 1 + 2 \\\\= \frac{1 - 2 + 2 }{2}\\\\= \frac{3}{2}$

$\frac{3}{2}$  is your answer .