Question

sin 30° + tan 45º - cosec 60°
sec 30° + cos 60° + cot 45°​

Answer 1

$\sin30 ^{0} + \tan {45}^{0} - \cosec {60}^{0} \ \sec {30}^{0} + \cos {60}^{0} + \cot {45}^{0} \\ = \frac{1}{2} + 1 - \frac{2}{ \sqrt{3} } \times \frac{2}{ \sqrt{3} } + \frac{1}{2} + 1 \\ = \frac{1 + 2}{2} - \frac{4}{3} + \frac{1 + 2}{2} \\ = \frac{3}{2} - \frac{4}{3} + \frac{3}{2} \\ = \frac{9 - 8 + 9}{6} \\ = \frac{10}{6} \\ = \frac{5}{3} \: \: \: ans \\ </p><p></p><p>\\❣ Hope \: it \: helps \: uhh❣$