Question

sin 300° × tan 330° × sec 420° / cotan 135° × cos 210° × cosec 315° =

Answer 1

sin300=sin(270+30)
= -cos30=-√3/2
tan330=tan(270+60)
=-cot60
=1/√3
sec(420)=sec(450-30)=cosec30=2
cotan(135)=cotan(180-45)=-cotan45=-1
cos210=cos(270-60)=-sin60=-√3/2
cosec315=cosec(360-45)= cosec45=1/√2
thus ,answer =-√3/2×1/√3×2/-1×-√3/2×1/√2
=-1/√3/2√2=2√2/√3

Answer 2

see first u have to turn all those degrees into simples forms
sin300.tan330.sec430/cot135.cos210.cosec315

sin( 360-60).tan(360-330).sec(360+60)/
cot(180-45).cos(360-150).cosec(360-45)

-sin60.-tan30.cos60/-cos45.cos(180-30).cosec45

√3/2*1/√3*1/2/-1.-cos(-30)*√2

1/4/√2*1/√3

=-1/2√3