Question

sin 35° cos 55° + cos 35° sin 55°/cosec10° – tan2 80°​

Answer 1

Step-by-step explanation:

$\sin(35 \cos(55 + \cos(35 = 10 \div 80 + 55 + 2 \times 155 \times \div 32 \div 35 \div \\ \\ so \sin( \cos(and \: tan \: ) ) ) ) ) 354 \div 80 \div \times 2 \div 80$

it com

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