Question

sin 35° cos55°+cos 35° sin55° divided by
cosec2 10°-tan2 80°
​

Answer 1

Answer:

hi

Step-by-step explanation:

sin 35× cos 55 = sin^2 35

cos 35× sin55= cos^2 35

cosec^2 10 - tan^2 80 =sec^2 80- tan^2 80

Solving we get value is 1/1=1

Answer 2

Step-by-step explanation:

sin35.cos55+cos35.sin55

son35.cos(90-35)+cos35.sin(90-35)

sin35.sin35+cos35.sin35

sin*2 35+cos*2 35

sin*2theta+cos*2theta=1

=1

cosec*2 10- tan*2 80

cosec*2 10- tan*2(90-10)

cosec*2 10- tan*2 10

cosec*2 theta - tan*2 theta = 1

=1

dividing sin35.cos55+cos35.sin55 by cosec*2 10- tan*2 80

= 1/1

= 1

Hope this helps you