Question

sin 37 /cos 53+ 2 tan 42/cot 48​

Answer 1

Answer:

sin 37 /cos 53+ 2 tan 42/cot 48

we know that sina = cos (90-a) and tana = (90-a)

=sin37/cos(90-37) +2× tan 42 /cot(90-42)

= sin37/sin37 +2× tan 42/tan42

=1+2×1

=1+2

=3