Math, asked by snehalmishra71, 3 months ago

Sin 3A = 3 sinA-4
sin³A.​

Answers

Answered by tajnemahendra
1

Answer:

sin(3a)

sin(2a+a)

=sin2a.cosa+cos2a.sina

=2sina.cosa.cosa+(cos²a-sin²a)sina

=2sina.cos² a+sina-2sin³a

=2sina(1-sin²a)+sina-2sin³ a

=2sina-2sin³a+sina-2sin³a

=3sin-4sin³a

Answered by amanraj56
0

Step-by-step explanation:

Sin 3A = 3 sinA-4

3sinA-4sin³A= 3 sinA-4

-4sin³A= -4

sin³A= -4/-4

sin³A=1

[formula : sin 3A= 3sinA-4sin³A]

#666

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