Math, asked by sajitazis7593, 9 months ago

Sin ^3a +cis ^3 a ÷sin a+cis a

Answers

Answered by sandy1816

1

Step-by-step explanation:

sin³a+cos³a/sina+cosa

=(sina+cosa)(sin²a-sinacosa+cos²a)/ (sina+cosa)

=1-sinacosa

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