Question

sin^3a-cos^3a/
sina-cosa
=1 +1/2sin 2a
​

Answer 1

Answer:

use formula of a ^3 - b^3

= (A-B)(A^2+ab+B^2)

and sin^2A + cos^2A = 2

so denominator and numerator including sina- cosa gets cancelled

so remaining is just 1+ sinA cosA