Question

Sin 3A= Cos (A-26°) what is the value of A​

Answer 1

Answer:

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Answer 2

Topic:-

Trigonometry

Question:-

Sin 3A= Cos (A-26°) what is the value of A

Solution:-

$Sin3A= Cos(A-26)$

$We \:know\: that\: Sin 3A= Cos(90-3A)$

$now\: we \:have\: to \:substitute \:there$

$Cos(90-3A) = Cos(A-26)$

$90-3A = A-26$

$90+26 = A+3A$

$116 = 4A$

$A= \dfrac{116}{4}$

$A= 29$

Answer:-

A=29

More Information:-

Trigon metric Identities

sin²θ + cos²θ = 1

sec²θ - tan²θ = 1

csc²θ - cot²θ = 1

Trigometric relations

sinθ = 1/cscθ

cosθ = 1 /secθ

tanθ = 1/cotθ

tanθ = sinθ/cosθ

cotθ = cosθ/sinθ

Trigonmetric ratios

sinθ = opp/hyp

cosθ = adj/hyp

tanθ = opp/adj

cotθ = adj/opp

cscθ = hyp/opp

secθ = hyp/adj

Multiples:-

$sin2\theta= 2sin\theta cos\theta$

$sin2\theta=\dfrac{2tan\theta}{1+tan²\theta}$

$cos2\theta= cos²\theta-sin²\theta$

$cos2\theta= 1-2sin²\theta$

$cos2\theta= 2cos²\theta-1$

$cos2\theta= \dfrac{1-tan²\theta}{1+tan²\theta}$

$tan2\theta= \dfrac{2tan\theta}{1-tan²\theta}$

$cot2\theta= \dfrac{cot²\theta-1}{2cot\theta}$