Math, asked by IshanDaiya, 1 year ago

sin 3A is equal to cos(A-6) where (3A) and (A - 6) are both acute angles then find the value of A

Answers

Answered by samriddhi77
3
sin3A = cos(A-6)
cos(90-3A) = cos(A-6)
90-3A = A-6
96= 4A
96/4= A
A= 24°
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Answered by rabinmukherjee6040
4

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