Math, asked by pranaygajbhe089, 4 days ago

(sin 3A - sin A)/(cos 3A + cos A)

Answers

Answered by bvpriya2016

0

Answer:

(sin3A+sinA)SinA+(cos3A−cosA)cosA

⇒2sin2A.cosA.sinA+2sin2A.sin(−A).cosA[∵sin−A=−sinA]

⇒2sin2A.cosAsinA−2sin2A.sinA.cosA=0

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