Question

Sin 3alpha / 1 + 2cos 2alpha​

Answer 1

Answer:

The prupose of this page is to prove the following formula: \sin 3x =4\sin x\sin(60^{\circ}-x)\sin(60^{\circ}+x). The easiest way to do that is to recourse to complex numbers and Euler's formula e^{i\theta}=\cos\theta +\sin\theta

Step-by-step explanation:

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Answer 2

Answer:

ok

Step-by-step explanation:

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