sin(3sin⁻¹1/3)=.........,Select Proper option from the given options.
(a) 23/27
(b) 1/3
(c) 27/23
(d) 2√3/9
Answers
Answered by
3
we have to find the value of sin{3sin^-1(1/3)}
Let sin^-1(1/3) = A
sinA = 1/3 ......................(1)
now, sin{3sin^-1(1/3)}= sin(3A)
we know, sin3x = 3sinx - 4sin³x
now, sin3A = 3sinA - 4sin³A
from equations (1),
sin3A = 3 × 1/3 - 4 × (1/3)³
= 1 - 4/27
= 23/27
so, sin{3sin^-1(1/3)}= sin(3A) = 23/27
hence, option (a) is correct.
Let sin^-1(1/3) = A
sinA = 1/3 ......................(1)
now, sin{3sin^-1(1/3)}= sin(3A)
we know, sin3x = 3sinx - 4sin³x
now, sin3A = 3sinA - 4sin³A
from equations (1),
sin3A = 3 × 1/3 - 4 × (1/3)³
= 1 - 4/27
= 23/27
so, sin{3sin^-1(1/3)}= sin(3A) = 23/27
hence, option (a) is correct.
Answered by
3
HELLO DEAR,
GIVEN:-
sin{3sin-¹(1/3)}
Let sin^-1(1/3) = A so, sinA = 1/3
now,
sin{3sin-¹(1/3)} = sin(3A)
WE KNOW:-
sin3x = 3sinx - 4sin³x
therefore,
sin3A = 3sinA - 4sin³A
[as sinA = 1/3]
sin3A = 3 * 1/3 - 4*(1/3)³
= 1 - 4/27 = (27 - 4)/27
= 23/27
so, sin{3sin^-1(1/3)} = sin(3A) = 23/27
hence, option (a) is correct.
I HOPE ITS HELP YOU DEAR,
THANKS
GIVEN:-
sin{3sin-¹(1/3)}
Let sin^-1(1/3) = A so, sinA = 1/3
now,
sin{3sin-¹(1/3)} = sin(3A)
WE KNOW:-
sin3x = 3sinx - 4sin³x
therefore,
sin3A = 3sinA - 4sin³A
[as sinA = 1/3]
sin3A = 3 * 1/3 - 4*(1/3)³
= 1 - 4/27 = (27 - 4)/27
= 23/27
so, sin{3sin^-1(1/3)} = sin(3A) = 23/27
hence, option (a) is correct.
I HOPE ITS HELP YOU DEAR,
THANKS
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