Question

sin (3x)/1+2cos(2x)​

Answer 1

Answer:

sinx

Step-by-step explanation:

since

{sin3x = 3sinx-4sin^3x and

cos2x= 1-2sin^2x}

hence the problem becomes

(3sinx - 4 sin^3x)/(1+2(1-2sin^2x))

sinx(3-4sin^2x)/(1+2-4sin^2x)

sinx(3-4sin^2x)/(3-4sin^2x)

= sinx