sin 3x=3sin x-4sin^3x
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Answer:
Sin3x=sin(x+2x)
=sinxcos2x +sin2xcosx
=sinx(1-2(sinx)^2)) + 2sinx((cosx)^2)
=sinx- 2(sinx)^3 +2sinx( 1-(sinx)^2)
=sinx - 2(sinx)^3 + 2sinx -2(sinx)^3
=3sinx - 4(sinx)^3
Step-by-step explanation:
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