Question

sin^3x+cos^3/sinx+cosx + sin^3x- cos^3x/sinx-cosx =2

Answer 1

${ \sin(x) }^{3} (+ - ) { \cos(x) }^{3} = (\sin(x) + \cos(x) )( { \sin(x) }^{2} + { \cos(x) }^{2}( + - ) \cos(x) \sin(x) ) \\ \\ so \: 1 + \sin(x) \cos(x) + 1 - \sin(x) \cos(x) = 2 \\ \\ hence \: proved$