sin^3x cos^3x integration
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Answer:
(1/4 sin^4)x(-1/6 sin^6)+c
Step-by-step explanation:
sin^3 x cos^2 x cos x dx
sin^3 x (1-sin^2x) as x dx
let u= sinx
du=cosxdx
u^3.(1-u^2) du = u^3-u^5 du
u^4/4 - u^6/6 +c
(1/4 sin^4) x(-1/6 sinx) +c
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