Math, asked by manish2974, 1 year ago

sin^3x cos^3x integration​

Answers

Answered by crowndestroyer
4

Answer:

(1/4 sin^4)x(-1/6 sin^6)+c

Step-by-step explanation:

sin^3 x cos^2 x cos x dx

sin^3 x (1-sin^2x) as x dx

let u= sinx

    du=cosxdx

u^3.(1-u^2) du =  u^3-u^5  du

u^4/4 - u^6/6 +c

(1/4 sin^4) x(-1/6 sinx) +c

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